((49k^-2)^3)/(7k^-8)

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Solution for ((49k^-2)^3)/(7k^-8) equation: 


D( k )

7*k^-8 = 0

k = 0

7*k^-8 = 0

7*k^-8 = 0

7*k^-8 = 0 // : 7

k^-8 = 0

k naleu017Cy do O

k = 0

k = 0

k in (-oo:0) U (0:+oo)

((49*k^-2)^3)/(7*k^-8) = 0

16807*k^2 = 0 // : 16807

k^2 = 0

k = 0

k in { 0} 

k belongs to the empty set

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